Pointers - 11 Pointers & functions - Passing array to function

Pointers & Functions - PASSING ARRAY TO A FUNCTION

        In this topic we will see how to pass an array to function. As we already know that simply writing array name or &a[0] will represent the address of first element of array(Refer  http://sridhanvantari.blogspot.com/2013/12/pointers-6-pointers-arrays.html ). From calling function pass this address to called function. In function, the receiver of this address must be a pointer. 

Now we will see how to pass numeric array to function,

/* Program to read and print array elements */

# include < stdio.h >
ArrayRead(p,n)
int *p,n;
{
int i;
printf("\nEnter the array elements ");
for(i=0;i    {
      scanf("%d",* ( p + i ) );
    }
}

ArrayPrint ( p, n )
int *p , n;
{
int i;
printf("\nThe array elements ");
for(i=0;i    {
      printf("%3d",* ( p + i ) );
    }
}

main ( )
{
int a[50] , n;

printf ( " \n Enter the size of array " );
scanf ( "%d", &n );

/* calling ArrayRead ( ) function, observe we are passing address of first element of array just by writing array name */

ArrayRead ( a, n);


/* calling ArrayPrint ( ) function, observe we are passing address of first element of array by writing &a[0] */

ArrayPrint ( &a[0], n );

}